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  Pressure DropÀÇ Ãß°¡¹®ÀÇ°Ç.
  ±Û¾´ÀÌ : Ǫ¸£¸¥ÅÊÀÌ   °íÀ¯ID : sigp77     ³¯Â¥ : 07-08-14 14:55     Á¶È¸ : 6225    
   ½ºÄµÃ¥ÀÚ.pdf (100.0K), Down : 60, 2007-08-14 14:55:56
Friction factor¸¦ °è»êÇÏ¿© ½ÇÁ¦ ¹è°üÀÇ ¾Ð·Â¼Õ½Ç¿¡ Àû¿ëÇØ º¸¾Ò½À´Ï´Ù¸¸,
°è»ê°ª°ú Ã¥ÀÚ(Chemical Engineering 1978,8,14)ÀÇ °ªÀÌ ³Ê¹« ´Ù¸¨´Ï´Ù.
¹«¾ùÀÌ À߸øµÇ¾úÀ»°¡¿ä.?
 
- Ã¥ÀÚ³»¿ë - (½ºÄµÇÏ¿© ÆÄÀϷΠ÷ºÎÇÏ¿´½À´Ï´Ù.)
1.Inside Diameter = 4.026 in
2.Flow rate = 137500 lb/hr
3.Temperature in = 490 F
4.Temperature out = 580 F
5.Mass velocity = 432 lb/s.ft2
6.Roughness, e = 0.00004572 m = 0.00015 ft
7.Avg. Specific Volume = 0.0194 ft3/lb
8.Viscosity avg. = 0.581 cP
9.Equivalent length, Le = 1131 ft
 
À§ÀÇ °ªÀ» °¡Áö°í Pressure dropÀ» ±¸Çϴµ¥, Ã¥ÀÚÀÇ Ç®ÀÌ´Â ´ÙÀ½°ú °°½À´Ï´Ù.
 
@Reynolds number = (4.026*1,555,200)/(12*0.581) = 898,000   <--- "1,555,200" ¾îµð¼­ ³ª¿Â°ª?

@Fanning Friction factor = 0.0038  <--- Á¦°¡ °è»ê½ÄÀ¸·Î °è»êÇغ» °ªÀº 0.004223 ÀÔ´Ï´Ù.

@DP = (0.00517) x (0.0038) x (432)^2 x (0.0194) x (1131)
                                  (4.026)
        = 20.0   psi
 
 
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¾Ë·ÁÁֽŠ¹æ¹ýÀ¸·Î ±¸ÇÑ Fanning friction factor°ª°ú ¸¹ÀÌ Â÷ÀÌ°¡ ³ª´Â°Í °°½À´Ï´Ù.
¿©·¯¹ø ¹ø°Å·´°ÔÇصå·Á Á˼ÛÇÕ´Ï´Ù.

½ºÅ×Æijë Stefano   07-08-14 21:43
Reynolds No °è»êÀÌ Æ²·ÁÀÖ½À´Ï´Ù.

Re = DG/¥ì = (4.026/12)*(432)/(0.581*6.72(10-4))=371,219
f(Darcy)=0.01764, Fannin's Frictioin Factor ff=0.004339
¥ÄP=(4 ff)*(L/D) *V^2/2*¥ñ =(0.01764)*(1131/(4.026/12)*(V^2)/2*(1000/0.0194/62.4)
=160274 Pa =1.634 kgf/cm2 or 23.25 psi

cf. V=432*0.0194 ft/s = 8.38 ft/s=2.5545 m/s
½ºÅ×Æijë Stefano   07-08-17 01:28
(1) ¾Æ½Ã´Â ¿£Áö´Ï¾î·ÎºÎÅÍ ¾î¶² ¼³¸íÀ» µéÀ¸¼Ì°ÚÁö¸¸  ¹¹°¡ ±×¸® º¹ÀâÇÑÁö ¹«Ã´ ±Ã±ÝÇÕ´Ï´Ù.  ´ÜÀ§È¯»êÀº °£´ÜÇÕ´Ï´Ù.

1 cP = 1 g/cm-s= 2.419 lbm/ft-h = 6.71(10-4) lbm/ft-s

(2) Á¡µµ°¡ 0.581 cP¶ó°í Çϸé Áú¹®¿¡¼­..

Re = DG/¥ì = (4.026/12 ft)*(432 lbm/ft2/s)/(0.581*6.72(10-4) lbm/ft-s)=371,219
              =  (4.026/12 ft)*(432*3600 lbm/ft2/h)/(0.581*2.419  lbm/ft-h)=371,250

h´ÜÀ§¸¦ ½è´À³Ä s´ÜÀ§¸¦ ½è´À³ÄÀÇ Â÷ÀÌ »Ó °°Àº °è»êÀÔ´Ï´Ù.  ´ÜÀ§È¯»ê ½Ã¿¡ ¼ö¹ÝµÈ À¯È¿¼ýÀÚÀÇ ¼ö¸¸ ´Ù¸¦ »ÓÀÔ´Ï´Ù.
Ǫ¸£¸¥ÅÊÀÌ    07-08-17 09:02
°¨»çÇÕ´Ï´Ù.
Á¤¸» ¸íÈ®ÇÏ°Ô ÀÌÇØ°¡ µÇ¾ú½À´Ï´Ù.~
½ºÅ×Æijë Stefano   07-08-17 11:24
Àá±ñ..  °è»êÀº ¸ÂÀºµ¥ ´ÜÀ§È¯»ê ¼³¸í¿¡¼­..¿ÀŸ°¡ ÀÖ¾ú³×¿ä.
1 cP = 0.01 P = 0.01 g/cm-s = 2.419 lbm/ft-h = 6.72(10-4) lbm/ft-s
   

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