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ÄÁÅÙÃ÷ | contents |
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½ºÅ͵ð | study |
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Á¦°¡ ¸Â°Ô ÇÑ°ÇÁö....; |
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±Û¾´ÀÌ : Keil °íÀ¯ID : Keil
³¯Â¥ : 00-00-00 00:00
Á¶È¸ : 5752
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<IMG SRC=""http://blogfile.paran.com/BLOG_47602/200604/1144518964_copy.jpg"">
Pb¸¦ hÀÇ ÇÔ¼ö·Î ³ªÅ¸³»¶ó. ¼öÀº À§¿¡´Â ±â¸§ÀÌ µé¾îÀÖ´Ù.
.........................................
À§Ä¡(³ôÀÌ)°¡ °°À¸¸é ¾Ð·ÂÀÌ °°À¸¹Ç·Î P©ü= P©ý
P©ü= P©û + (0.88*9.8*h/2)
P©ý= Pa + (13.6*9.8*h)
{P©û + (0.88*9.8*h/2)} = { Pa + (13.6*9.8*h) }
P©û= Pa + (13.6*9.8*h) - (0.88*9.8*h/2)
Pb = P©û+ (0.88*9.8*0.3) À̹ǷÎ
Pb = Pa + (13.6*9.8*h) - (0.88*9.8*h/2) + (0.88*9.8*0.3)
= Pa + 129.0*h + 2
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