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ÄÁÅÙÃ÷ | contents |
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½ºÅ͵ð | study |
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Stefano´Ô.... |
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±Û¾´ÀÌ : Keil °íÀ¯ID : Keil
³¯Â¥ : 00-00-00 00:00
Á¶È¸ : 6378
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<META NAME=""ROBOTS"" CONTENT=""NOINDEX, NOFOLLOW"">
°è»ê±âÁØ 1 min
µµÀÔ·®
¹ßÈ¿¾×(¼ö¿ë»ó) + À¯±â¿ë¸Å(ÃßÃâ¿ë¸Å)
= 100L + 9.5L
¹èÃâ·®
¼ö¿ë»ó(Æó±â¹°) + À¯±â»ó
=100 L + 9.5 L
¼ººÐ¼öÁö => È¿¼Ò
µµÀÔ·®
¹ßÈ¿¾× : 100L * 10.2 g/L = 1020g
=> 1020 + 0
¹èÃâ·®
F(À¯±â»ó) + W(¼ö¿ë»ó)
=> 1020 = F + W
[F/9.5 (g/L À¯±â»ó)]/[W/100 (g/L ¼ö¿ë»ó)] = 18.5g
=> F = 1.76W
1020 = 1.76W + W
W = 369.57
F = 650.43
È¿¼ÒÀÇ È¸¼öÀ² = (650.43/1020) * 100 = 64%
ȸ¼ö¼Óµµ = 650.43 g/min
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