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ÄÁÅÙÃ÷ | contents |
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½ºÅ͵ð | study |
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¸ôºÐÀ²·Î °è»êÇß½À´Ï´Ù. |
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±Û¾´ÀÌ : ¹®º´ÀÇ °íÀ¯ID : ¹®º´ÀÇ
³¯Â¥ : 00-00-00 00:00
Á¶È¸ : 14536
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Ç×»ó Ä£ÀýÇÑ ´äº¯¿¡ °¨»çÇÏ°Ô »ý°¢ÇÏ°í ÀÖ½À´Ï´Ù.
Á¦°¡ °è»êÇÑ°Í¿¡ ¹®Á¦°¡ ÀÖ´Â °Í °°¾Æ ´Ù½ÃÇѹø ¿©Âå º¾´Ï´Ù. 2105) Áú¹® ÀÌ¿¹¿ä
¿ì¼± ¸ôºÐÀ²À» ÅëÇÑ ¾ËÄÝ ¿ë¾×ÀÇ Æ÷È Áõ±â¾ÐÀ» ±¸Çß½À´Ï´Ù.
¾ËÄÝÀÇ ¹«°Ô 1.532cc * 0.79 (¹Ðµµ ȯ»ê) = 1.21028g ¹°ÀÇ ¹«°Ô : 998.468g
Moles Ethanol = 1.532/46 =0.033304
Moles Water = 998.468/18.02=55.40887
(Mole Fraction, f) = (No. of Moles of a Component)/(Total No. of Moles of the Solution) --------(1)
X ethanol = 0.033304 / (0.033304+55.40887)= 0.0006006
X water = 55.40887/ 55.44217 = 0.9993993
(Partial (Vapor) Pressure of a Component, P) = (Pure Component Vapor Pressure,P£§)*(Mole Fraction,f) ---(2)
ºÎºÐ¾Ð ethanol : 97.461 torr * 0.0006006 =0.058535 torr
ºÎºÐ¾Ð water : 39.903 torr * 0.9993993 =39.879030 torr
2107 ¹øÀÇ Áú¹®¿¡ ÀÖ´Â 5) ¿¡ ÀÖ¾î À§ÀÇ ½ÄÀ» Àû¿ëÇؼ °è»ê Çغ¸¾Ò½À´Ï´Ù.
°ø±â»ó´ë½Àµµ(R)-->¼öÁõ±â ºÐ¾Ð(Pw)°è»ê-->¾ËÄݺоÐ(Pa)°è»ê
(¼öÁõ±â ºÐ¾Ð, Pw) = (Æ÷ȼöÁõ±â¾Ð) * (»ó´ë½Àµµ,R) : »ó´ë ½Àµµ°¡ 80% ÀÏ°æ¿ì
39.903 * 0.8 = 31.9224 (torr)
(¾ËÄÝ ºÐ¾Ð,Pa) = (¼öÁõ±â ºÐ¾Ð)*(¾ËÄÝÁõ±â¾Ð*¾×»óÀÇ ¾ËÄݸôºÐÀ²)/(Æ÷ȼöÁõ±â¾Ð*¾×»óÀÇ ¹°ÀÇ ¸ôºÐÀ²)
31.9224 torr * 0.058535 torr * 0.0006006 / 39.903 torr * 0.9993993
=0.001118778/ 39.879030 = 0.000028054 torr
µû¶ó¼ ¾ËÄÝÀÇ ³óµµ´Â 1000cc flow¸¦ ÅëÇØ ³ª°£´Ù°í °¡Á¤ÇÒ °æ¿ì
0.000028054/760 = x /(1000 +x)
0.000000036 = x / (1000 +x)
x= 0.000036913
0.0369ppm
½ÇÁ¦ ³óµµ´Â 230ppm Á¤µµ Àε¥.. ¿ÀÂ÷°¡ ¸¹ÀÌ ³ª¼..
¹°°ú ¾ËÄÝÀÌ ¼¯À϶§ °°Àº ºÎÇÇ·Î ´Ã¾î³ª´Â °¡¿ä?
ÃʵîÇб³¶§ ¾Ë°»ÀÌ°¡ Å« ÄáÀ̶û ÀÛÀº ¸ð·¡¸¦ ¼¯À¸¸é ¹«°Ô´Â ´Ã¾î³ªÁö¸¸
ºÎÇÇ´Â µ¿ÀÏÇÑ ½ÇÇèÀ» ÇÑÀûÀÌÀִµ¥... ¹°°ú ¾ËÄÝ,, ¿ë¾×¿¡¼´Â ±×°°Àº Çö»óÀÌÀִ°ÇÁö¿ä?
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