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PP=(753+136[1-exp(-0.15v100)]-572S+0.0512v100+0.139x1.8MeABP)/1.8
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PP=234.85 x S^2.970566 x M^(0.61235 - 0.473575xS) x v100^(0.310311 - 0.32834xS)
v100=kinematic viscosity at 100F,cSt
S = specific gravity
M = molecular weight of petroleum fraction
MeABP = Mean Average Boiling Point,R
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