¾Æ·¡´Â ¾ÆÀ̵ð È°ø¼Ò³à°¡ ¿Ã¸° ¹®Á¦ ÀÔ´Ï´Ù.
T=À¯Ã¼¿Âµµ=±Ý¼ÓÇ¥¸é(Æò±Õ)¿Âµµ=(510+496.2)/2= 503.1¡É
t=º¸¿ÂÀç Ç¥¸é¿Âµµ=19.4¡É
k=º¸¿ÂÀç·áÀÇ ¿Àüµµµµ = 0.053 kcal/h/m/¡É
q=º¸¿ÂÀ縦 ÅëÇÑ ´ÜÀ§ ±æÀÌ´ç ¿Àü´Þ ¼Óµµ
x=º¸¿ÂÀç·áÀÇ µÎ²²=0.2 m
Am=º¸¿ÂÀç·á ´ÜÀ§ ±æÀÌ´ç ´ë¼ö Æò±Õ Àü¿¸éÀû,
=¥ð * {(0.8064-0.4064)/ln(0.8064/0.4064)}*1 =1.8270
q=(k/x)*Am*(T-t)=(0.053/0.2)*{1.8270}*(503.1-19.4)
= 234.2 kcal/h/m
Àüü±æÀÌ¿¡ ´ëÇÑ ¿¼Õ½Ç
Q = 234.2*4000=936,800 kcal/h
Áú¹®) ´ë¼öÆò±ÕÀü¿¸éÀûÀÇ ´ÜÀ§°¡ m2À̹ǷÎ, qÀÇ ´ÜÀ§´Â kcal/h¾Æ´Ñ°¡¿ä?
qÀÇ ´ÜÀ§°¡ kcal/h/m°¡ ¸Â´Â°Í °°Àºµ¥, °è»êÀ» Çϸé kcal/h·Î ³ª¿É´Ï´Ù.
´ë¼öÆò±ÕÀü¿¸éÀûÀÇ ´ÜÀ§ mÀ̸é, qÀÇ ´ÜÀ§´Â kcal/h/mÀÌ°í, ¾îµð°¡ À߸ø µÇ¾ú´ÂÁö¿ä?