ÀÚµ¿·Î±×ÀÎ
ÄÁÅÙÃ÷ | contents
ÀϹݰԽÃÆÇ
Q&A°Ô½ÃÆÇ
°øÇÐ S/W
½ºÅ͵ð | study
´ÜÀ§È¯»ê
³óµµ°è»ê
ÀϹÝÈ­ÇÐ
È­°øÀϹÝ
È­°ø½Ç¹«

   
  ÁßÈ­ ÀûÁ¤ ºñÀ²À» ¾Ë°í½Í¾î¿ä
  ±Û¾´ÀÌ : °ø´ë²ÃÅë   °íÀ¯ID : atc112     ³¯Â¥ : 09-04-07 00:18     Á¶È¸ : 4503    
½ºÅ×Æijë´Ô!!! Áö³­¹ø ´äº¯ °¨»çµå¸³´Ï´Ù.
 
±×·³ ´Ù½ÃÇѹø...
 
Àú¹ø Áú¹®À̶û ºñ½ÁÇϸ鼭 ¾à°£ ´Ù¸¥°Çµ¥¿ä
 
96%ÀÇ Áú·®ºÐÀ²À» °¡Áø Ȳ»ê(H2SO4) 320L¸¦ ¼ö»êÈ­³ªÆ®·ý(NaOH)À¸·Î ÁßÈ­½ÃÄÑ¾ß µÇ´Âµ¥¿ä
 
1:2 ¹ÝÀÀºñ´Â °íµîÇб³¶§ °è¼Ó Çؼ­ ¾Ë°Ú´Âµ¥
 
¸·»ó °è»êÇÏ·Á´Ï ¾ÈµÇ´Â±º¿ä.¤Ð
 
¼ö»êÈ­³ªÆ®·ýÀÌ ¾ó¸¶³ª ÇÊ¿äÇÑ°¡¿ä???
 
½ºÅ×Æijë´Ô!!! ºÎŹµå¸®°Ú½À´Ï´Ù.¤Ð

Stefano    09-04-07 15:08
(»êÀÇ ´ç·® ¼öÈ¿)=(¾ËÄ«¸®ÀÇ ´ç·® ¼öÈ¿)

(»êÀÇ ´ç·® ¼öÈ¿ )=(Áú·®=ºÎÇÇ*¹Ðµµ)*(Áú·® ºÐÀ²)/(»êÀÇ ºÐÀÚ·®/»ê°¡)
=(320L * ¹Ðµµ,kg/L)*(0.96)/(98/2)

(ÇÊ¿äÇÑ ¾ËÄ«¸® ´ç·®¼öÈ¿)=(»êÀÇ ´ç·®¼öÈ¿)
(¹Ð¿äÇÑ ¾ËÄ«±â Áú·®)=(¾ËÄ«¸®ÀÇ ´ç·® ¼öÈ¿)*(¾ËÄ«¸®ÀÇ ºÐÀÚ·®/¿°°¡)

NaOHÀÇ ´ç·®= 40g/eq.
H2SO4ÀÇ ´ç·®=98g/2 =49 g/eq.
   

Copyright 1999.07.10-Now ChemEng.co.kr & 3D System Engineering. (mail : ykjang@naver.com, call 010-4456-8090)