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  ±Û¾´ÀÌ : È«Á¤¹Î   °íÀ¯ID : hong9811     ³¯Â¥ : 11-03-12 20:20     Á¶È¸ : 6681    
Gasoline(specific gravity = 0.70) and kerosene(specific gravity = 0.82) are blend to obtain a mixture
 
with a specific gravity of 0.78 Calculate the volumetric ratio(volume of gasoline/volume of kerosene)
 
of the two compounds in the mixture, assuming V(blend) = V(gasoline) + V(kerosene)
 
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¿©±â¼­ °¡¸£ÃÄ ÁÖ½ÃÁö ¾ÊÀ»±î Çؼ­ °¡ÀÔÇÏ°Ô µÇ¾ú½À´Ï´Ù.

¸ð¹ü»ý mbsahg   11-03-13 14:49
½ÄÀº ÇϳªÀε¥ º¯¼ö°¡ µÎ°¡ÁöÀÔ´Ï´Ù.(ÀÚÀ¯µµ¸¦ È®ÀÎÇغ¸½Ê½Ã¿ä,)
ºñÁßÀº GasolineÀÌ 0.7, keroseneÀÌ 0.82À̹ǷΠ´ÙÀ½°ú °°Àº ½ÄÀ» ¸¸µé¼ö ÀÖ½À´Ï´Ù.
0.7X + 0.82Y = 0.78  ------ assuming V(blend) = V(gasoline) + V(kerosene)
¿©±â¼­ X´Â GasolineÀÇ Á¶¼º(ºÎÇǺñ) Y´Â keroseneÀÇ Á¶¼ºÀÔ´Ï´Ù.
µû¶ó¼­ º¯¼öÇϳªÀÇ °ªÀ» Á¤ÇØ ¹Ýº¹ÀûÀ» °è»êÀ» ÇؾßÇÕ´Ï´Ù. ¿¢¼¿·Î °è»êÇÏ½Ã¸é ±Ý¹æ ±¸ÇÒ¼ö ÀÖ½À´Ï´Ù.
¸ð¹ü»ý mbsahg   11-03-14 14:46
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µû¶ó¼­ °£´ÜÈ÷ ±¸ÇÒ¼ö ÀÖ½À´Ï´Ù.

0.7X + 0.82Y = 0.78  ------ assuming V(blend) = V(gasoline) + V(kerosene)
X + Y = 1
À§ÀÇ µÎ½ÄÀÌ ¸¸µé¾î Áý´Ï´Ù.
³ª¸ÓÁö´Â ¿¬¸³¹æÁ¤½ÄÀ¸·Î Ç®¸é ¹Ù·Î ³ª¿É´Ï´Ù.
½ºÅ×Æijë Stefano   11-03-16 22:58
Æò±Õ¹Ðµµ´Â ¾Õ¼± ´ä±Ûó·³ "ºÎÇÇ ºÐÀ²"À» ±âÁØÀ¸·Î ÇØ¾ß ¼±Çü(1Â÷½Ä)À¸·Î °è»êµË´Ï´Ù 

(Average Density) =0.7+(0.82-0.7)*Y ...................................(1) Y=volume fraction of the heavier
(Average Density) =0.7+(0.82-0.7)*(1-X) =0.82-(0.82-0.7)*X ..(2) X=volume fraction of the lighter.
   

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