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pH¸¦ Á¶ÀýÇϱâ À§ÇÑ NaOH ÁÖÀÔ·® °ü·ÃÇÏ¿© Áú¹®µå¸³´Ï´Ù.
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: kohc7
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: 09-11-04 11:39
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¹° 4tonÀÇ pH°¡ 8À϶§ pH10À¸·Î Á¶ÀýÇϱâ À§ÇÏ¿© 5% / 25% / 50% NaOH¿ë¾×À» °¢°¢ ¾ó¸¶³ª Åõ¿©ÇØ¾ß ÇÒ±î¿ä?
°è»êÀ» Çغôµ¥ 5% NaOH ÇÊ¿ä·®ÀÌ 38ml°¡ ³ª¿À³×¿ä...³Ê¹« ÀûÀº¾çÀ̶ó Ʋ¸°°Í °°Àºµ¥...
°í°ß ºÎŹµå¸³´Ï´Ù. °¨»çÇÕ´Ï´Ù.
½ºÅ×Æijë
Stefano
09-11-04 13:58
(1) ÅõÀÔÇÏ´Â NaOH¿¡ Æ÷ÇÔµÈ ¹°ÀÇ ¾çÀ» ¹«½ÃÇÏ°í °è»êÇϸé
pOH = 14 - pH = 14-10 = 4
[OH-]=10^-4 kg-mol/L
ÇÊ¿äÇÑ [NaOH] = {4000 kg * 1 L/kg} * 10^-4 kg-mol/L = 0.4 kg-mole NaOH or 16 kg NaOH
5w% SolutionÀÎ °æ¿ì ¿ë¾×ÀÇ Áú·® = 16/0.05 = 320 kg 5w% NaOH Solution
(2) ¾î¶»°Ô °è»êÇؼ ±×·± °á°ú°¡ ¾ò¾îÁ³´ÂÁö ¸ð¸£Áö¸¸
pHÀÇ Á¤ÀÇ, ±×¸®°í [OH-]³óµµ °è»ê¹æ¹ý µîÀ» ´Ù½Ã Á¡°ËÇؼ °è»êÇØ º¸¼¼¿ä.
(1) ÅõÀÔÇÏ´Â NaOH¿¡ Æ÷ÇÔµÈ ¹°ÀÇ ¾çÀ» ¹«½ÃÇÏ°í °è»êÇϸé pOH = 14 - pH = 14-10 = 4 [OH-]=10^-4 kg-mol/L ÇÊ¿äÇÑ [NaOH] = {4000 kg * 1 L/kg} * 10^-4 kg-mol/L = 0.4 kg-mole NaOH or 16 kg NaOH 5w% SolutionÀÎ °æ¿ì ¿ë¾×ÀÇ Áú·® = 16/0.05 = 320 kg 5w% NaOH Solution (2) ¾î¶»°Ô °è»êÇؼ ±×·± °á°ú°¡ ¾ò¾îÁ³´ÂÁö ¸ð¸£Áö¸¸ pHÀÇ Á¤ÀÇ, ±×¸®°í [OH-]³óµµ °è»ê¹æ¹ý µîÀ» ´Ù½Ã Á¡°ËÇؼ °è»êÇØ º¸¼¼¿ä.
ÇؾçÈ°ø
kohc7
09-11-06 11:28
°¨»çÇÕ´Ï´Ù. ´Ù½Ã °è»êÇØ º¸µµ·Ï ÇÏ°Ú½À´Ï´Ù.
°¨»çÇÕ´Ï´Ù. ´Ù½Ã °è»êÇØ º¸µµ·Ï ÇÏ°Ú½À´Ï´Ù.
½ºÅ×Æijë
Stefano
09-11-06 12:28
¾Ñ ÇÊÀÚÀÇ °è»êÀÌ Æ²·Á ÀÖ½À´Ï´Ù. g-mole/L°¡ kg-mole/L·Î °è»êµÇ¾ú½À´Ï´Ù. ¾Æ·¡¿Í °°ÀÌ Á¤Á¤ÇÕ´Ï´Ù.
pOH = 14 - pH = 14-10 = 4
[OH-]=10^-4 g-mol/L
ÇÊ¿äÇÑ [NaOH] = {4000 kg * 1 L/kg} * 10^-4 g-mol/L = 0.4 g-mole NaOH or 0.016 kg NaOH
5w% SolutionÀÎ °æ¿ì ¿ë¾×ÀÇ Áú·® = 0.016/0.05 = 0.320 kg 5w% NaOH Solution
¹Ðµµ°¡ 1 g/cc¶ó°í °¡Á¤ÇÏ¸é ¾à 320 ml
¾Ñ ÇÊÀÚÀÇ °è»êÀÌ Æ²·Á ÀÖ½À´Ï´Ù. g-mole/L°¡ kg-mole/L·Î °è»êµÇ¾ú½À´Ï´Ù. ¾Æ·¡¿Í °°ÀÌ Á¤Á¤ÇÕ´Ï´Ù. pOH = 14 - pH = 14-10 = 4 [OH-]=10^-4 g-mol/L ÇÊ¿äÇÑ [NaOH] = {4000 kg * 1 L/kg} * 10^-4 g-mol/L = 0.4 g-mole NaOH or 0.016 kg NaOH 5w% SolutionÀÎ °æ¿ì ¿ë¾×ÀÇ Áú·® = 0.016/0.05 = 0.320 kg 5w% NaOH Solution ¹Ðµµ°¡ 1 g/cc¶ó°í °¡Á¤ÇÏ¸é ¾à 320 ml
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