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물질수지문제

글쓴이 : now 고유ID : naomily 날짜 : 11-04-22 19:45 조회 : 3627

•As mined, iron ore contains three times the percentage of iron oxide as other solid impurities. Water is used to transport the iron ore into a separator. Two streams emerge from the separator: the washed ore stream has 62.8 % iron oxide, 3.8% solid impurities and water as the remainder . The waste stream has 3.6% iron oxide, 33.7% solid impurities and water as the remainder. The total washed ore stream flow rate is 37.2 tonnes/hr. All percentages are by mass.

•Determine:

i) the output (t/hr) of iron oxide plus solid impurities from

the washed ore stream

ii) the total water output (t/hr)

iii) the input stream (t/hr)

•힌트 좀 주세요.

끔찍한아이 mgood2

11-04-22 21:49

mass balance

Stefano

11-04-22 23:55

I = Iron Ore Net Mass Flow
S= Solid Net Mass Flow = 3*I as given in the problem.
F = I + S = Input Mass Flow <==Qiii

O=Washed Ore=37.2 t/h
W=Mass Flow of Water
WW=Mass Flow of Waste Water <==Qii

Iron Ore Balance: I = 37.1*(62.8%) + WW*(3.6%).............................(1)
Solid Balance: S = 3*I = 37.2*(3.8%) + WW*(33.7%)...................(2)

I, WW, and S can be calculated from Eq(1) and (2)
Eventually..WW(=Qii) would be 299.8742 t/h

Qi = ??, Q2=WW, Qiii = ??

now naomily

11-04-23 15:14

정말 감사합니다.