A 20% glucose solution flows from a mixing tank at 50 kPa through an horizontal pipe 5 cm in diameter at 25 m3/h. If the pipe diameter reduces to 3 cm, calculate the new pressure in the pipe (the density of glucose solution is 1090 kg/m3).
흐름속도=25/3600m3s-1
5cm단면적=π /4d2=π /4*(0.05)2=0.00196 a1
유속 =(25/3600)/(1.96*10-3)
3cm단면적=π /4d2=π /4x(0.03)2=0.0007065 a2
유속 =(25/3600)/(7.06*10-3)
베르누이 공식 써서 0+(1.96*10-3)/2+50*(10)3/1090=0+(7.06*10-3)/2+p2/1090
=0+0.00098+45.87=0+0.0070+p2/1090
p2/1090=(45.87-0.0070)
p2= 45.86kpa
풀어 봤는데 틀린부분 지적해주세요.
