A single-effect evaporator is to produce a 35% solids tomato concentrate from a 6% solids raw juice entering at 18°C. The pressure in the evaporator is 20 kPa(absolute) and steam is available at 100 kPa gauge. The overall heat-transfer coefficient is 440 J m-2 s-1 °C-1, the boiling temperature of the tomato juice under the conditions in the evaporator is 60°C, and the area of the heat-transfer surface of the evaporator is 12 m2. Estimate the rate of raw juice feed that is required to supply the evaporator.
요약: raw juice 6%고체로부터 토마토35% 증발 ,증발에 요구되는 raw juice 속도?
토마토 비열 어는점 이상 3.98
고형분 수지 0.06f=0.35p
스팀21kpa로 가정했을때 (2539.9-88.14)
100kpa일 때 포화수증기표보고 했는데요.
s(질량속도)= (440)*(12)(온도차)/스팀Hs-hs(2676.1-419.04*10^3)
그 다음부터 어떻게 해야 될지 잘 모르겠어요. 힌트 좀 주세요.
