아레니우스식으로 한다고 배웠는데
a reaction, in the presence of a certain amount of enzyme,was found to have a vmax of 61.7nmols-1
at 25℃.in the presence of the same amount of enzyme at 37℃, the vmax was 120.8nmols-1. using sensitive detection techniques it was possible to follow the course of the uncatalysed reaction, which had a rate of 30.2ⅹ10-3 nmols-1 at 25℃ and 88.4ⅹ10-3 nmols-1 at 37℃. calculate the activation energy for the catalysed and uncatalysed reactions.
k=Ae-Ea/RT
61.7=a*?(8.314*298)
R:기체상수(8.314),T:절대온도,A:그반응조건에고유한상수,Ea:활성화에너지 k는ㄴ 속도 상수
활성화에너지를 구해야되는데 a에 뭘 대입해야되는거죠?
