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  Èñ¼®¹è¼ö¿¡ ´ëÇÏ¿©...
  ±Û¾´ÀÌ : ±èÁ¤È¯   °íÀ¯ID : ±èÁ¤È¯     ³¯Â¥ : 00-00-00 00:00     Á¶È¸ : 9571    
97% Ȳ»ê ----> 5N Ȳ»ê 50ml

·Î ¸¸µå´Â °úÁ¤ÀÔ´Ï´Ù

À̶§ NV=N£§V£§ ¶ó´Â °ø½ÄÀ» ¾²¸é °£´ÜÇÏÁÒ?

1.84(Ȳ»êÀÇ ºñÁß) * (97g/100ml) * 1000ml * (1/49g)(´ç·®´ë ´ç·®ºñ À̹ǷÎ..)

ÀÌ·¸°Ô Çϸé 36.42N ÀÌ ³ª¿ÀÁÒ

¿©±â¼­ 36.42N * x = 5N * 50ml  (¾Æ±î °ø½Ä¿¡ ´ëÀÔÇÏ¿©..)

ÀÌ·¸°Ô ÇÏ¸é °£´ÜÇѵ¥¿ä

°ø½ÄÀ» »ç¿ëÇÏÁö ¾Ê°í Èñ¼®¹è¼ö¸¦ ÀÌ¿ëÇÏ¿© Ç®À̸¦ ÇÏ·Á¸é

¾î¶»°Ô ÇؾßÇϳª¿ä?

Stefano Stefano   39-08-02 00:00
"°ø½Ä"À» ¿Ü¿ö »ç¿ëÇÏ´Ùº¸¸é ÈçÈ÷ Ʋ¸®±â ½±½À´Ï´Ù.

´ÙÀ½ ¼ø¼­·Î °è»êÇϸé Á÷°üÀûÀÌ¶ó¼­ Æ²¸®Áö ¾Ê½À´Ï´Ù.

(1)5N Ȳ»ê 50 mlÁß¿¡ µé¾î Àִ Ȳ»êÀÇ ·®
= (5 g-eq-H2SO4/1000ml)*50 ml = 0.25 g-eq-H2SO4
= (0.25 g-eq-H2SO4) * (98/2 g/g-eq-H2SO4)   
= 12.25 g-H2SO4

(2) 97% Ȳ»êÀ¸·ÎºÎÅÍ ÃëÇØ¾ß ÇÒ È²»êÀÇ ·®À» W¶ó°í Çϸé 
(97% * W g-97%H2SO4)= 12.25 g-H2SO4....(À̽ÄÀº ±»ÀÌ ¾µ ÇÊ¿ä´Â ¾øÁö¿ä.)

µû¶ó¼­
W g-97%H2SO4 = (12.25 g-H2SO4)/97% 
= 12.63 g-97%H2SO4 .....................(Ans1)

(3)ÇÊ¿äÇÑ 97%H2SO4¸¦ ºÎÇǷΠȯ»êÇϸé
=12.63 g-97%H2SO4/(1.84 g/ml) = 6.86 ml 97%H2SO4...(Ans2)

º¹ÀâÇÑ °Í °°Áö¸¸ ´Ü°èº°·Î Á÷°üÀûÀÌ¶ó¼­ °Ë»êµµ ½±½À´Ï´Ù.

"Èñ¼®¹è¼ö"¶ó´Â ´Ü¾î´Â ÇÊÀÚÀÇ °í±³½ÃÀý¿¡´Â µé¾îº¸Áö ¸øÇß½À´Ï´Ù.  ÀÌ ¿ë¾î¸¦ µµÀÔÇϸ鼭 ÇлýµéÀ» ´õ¿í È¥µ¿½º·´°Ô ¸¸µç °Í °°½À´Ï´Ù.
(»ç½Ç ³óµµ ¹®Á¦´Â ÃʵîÇб³³ª ÁßÇб³ ¼öÁØÀÇ »ê¼ö¹®Á¦À̰ŵç¿ä. ÇÊÀÚ »ý°¢À¸·Î´Â "°ø½Ä"ÀÌ ±³À°À» ¸Ûµé°Ô ÇÏ°í ÀÖ½À´Ï´Ù.)


"Èñ¼®¹è¼ö"¶ó´Â ¿ë¾î¸¦ ±»ÀÌ µµÀÔÇؼ­ À­ ¹®Á¦¸¦ Ǭ´Ù¸é ºñ·Ê½ÄÀ¸·Î 

(36.42N)/(5N)= 7.28 ¹è Èñ¼®
µû¶ó¼­ ¿ø·¡ÀÇ ºÎÇǸ¦ 7.28¹è Èñ¼®Çؼ­ 50ml¸¦ ¸¸µé·Á°í ÇÑ´Ù¸é

V*7.28 = 50 ml
µû¶ó¼­

V = 50 ml/7.28 =6.86 ml

½ÄÀº °£´ÜÇØ º¸ÀÌÁö¸¸ ¿Ö ±×·¸°Ô µÇ´ÂÁö ¸ð¸£¸é ¸Â´ÂÁö Ʋ¸®´ÂÁö °Ë»êÀÌ ¾È µÅ¼­ ÀÚ½ÅÀÌ ¾øÀ» °ÍÀÔ´Ï´Ù.

Çб³ ±³À°¿¡¼­ "°ø½Ä"À» °­Á¶ÇÑ´Ù´Â °ÍÀº À߸øµÈ ±³À°À̶ó°í »ý°¢µË´Ï´Ù.  ¸ðµç °ÍÀ» ¾Ï±â½ÄÀ¸·Î¸¸ °¡¸£Ä¡´Â °á°ú¸¦ °¡Á®¿À°í º»·¡ÀÇ Àǹ̴ »ç¶óÁ® ¹ö¸³´Ï´Ù.  ¶æÀ» ¸ð¸¥ ä ¾Ï±âÇÏ´Â °ÍÀº ¾ûÅ͸® ±³À°¹æ¹ýÀÌÀÚ °øºÎ¹æ¹ýÀÔ´Ï´Ù.
±èÁ¤È¯ ±èÁ¤È¯   39-08-02 00:00
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