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Stefano Stefano   39-08-02 00:00
¼öÁõ±â´Â ÀüÇظ¦ ÇÏÁö ¾ÊÀ» °ÍÀÌ°í ºÐÀÚ°£ÀÇ °Å¸®°¡ ¸Ö¾î Àüµµµµ°¡ 0À¸·Î ³ªÅ¸³ª°Ú°í ¹°ÀÇ °æ¿ì¿¡´Â ´ÙÀ½°ú 0.0548 ¸¶ÀÌÅ©·ÎÁö¸à½º/¼¾Æ¼¹ÌÅÍ Á¤µµ¶ó³×¿ä.
VLSI ¹ÝµµÃ¼¿ë ¼ø¼ö´Â 0.06 Á¤µµÀÌ°í..

"As we try to make pure water by gradually removing electrolytes, its conductivity gradually decreases. So, if all electrolytes are removed, will its conductivity become zero? No. Why? Because an infinitesimal part of the molecules of water--only about one in 500 million--is ionized as hydrogen ions () and hydroxide ions (). Theoretically, at this point, the conductivity becomes 0.0548 µS/cm at 25 ¡ÆC.

The conductivity of water used in the production of VLSIs in the semiconductor industry is below 0.06 µS/cm-- that£§s water of very high purity indeed. Such water is referred to as ultrapure water. Without going to such an ultrapure level, conductivity of water can be lowered to below 1 µS/cm through a process of deionization. Such water is called ion-exchanged water or deionized water. When we talk about pure water, we refer to water of this level of purity. When water comes in contact with air, carbon dioxide is dissolved in water, causing its conductivity to rise by about 1 µS/cm. This does affect the conductivity of pure water.?
   

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