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  ¼ö·ÂÇÐÀû Á÷°æ(Hydraulic Diameter)ÀÇ °³³ä¿¡ ´ëÇØ ¾Ë°í½Í½À´Ï´Ù.
  ±Û¾´ÀÌ : dpffkqlwpf   °íÀ¯ID : dpffkqlwpf     ³¯Â¥ : 13-02-15 17:40     Á¶È¸ : 8283    
   µîº¯»ç´Ù¸®²ÃÀÏ ¶§ »ó´çÁ÷°æ.pdf (226.5K), Down : 79, 2013-02-15 17:40:20
ÀÏ´Ü À¯Ã¼¿ªÇÐÀ̳ª ¿­Àü´Þ¿¡¼­ º¸¸é Ã¥¸¶´Ù ´Ù¸£°Ô Ç¥±âµÇ¾îÀÖ´Â °æ¿ì°¡ ¸¹½À´Ï´Ù.(¿ë¾î¿¡ ´ëÇؼ­..)
»ó´çÁ÷°æ(Equivalent Diameter), ¼ö·ÂÇÐÀû Á÷°æ(Hydraulic Diameter).
 
¿©±â¼­ Áú¹®µå¸®°í ½ÍÀº »çÇ×Àº
 
¹Ý Á¤µµ Âù µîº¯»ç´Ù¸®²Ã ÆÄÀÌÇÁÀÇ °æ¿ì ¼ö·ÂÇÐÀû Á÷°æÀ» ±¸ÇÏ·Á°í ÇÕ´Ï´Ù.
ÀÌ °æ¿ì Perry handbookÀÇ Á¤ÀÇ·Î µû¸£¸é
 
'Four times the channel cross-sectional area divided by the wetted perimeter.'
'´Ü¸éÀû¿¡ 4¹è¸¦ ÃëÇÑ °ª¿¡ Á¥Àº µÑ·¹·Î ³ª´©¾îÁØ´Ù.' ¶ó°í µÇ¾îÀÖ½À´Ï´Ù.(6-12 Fluid and Particle Dynamics Âü°í)
 
±×·±µ¥ ¿©±â¼­ ´Ü¸éÀûÀ» ÃëÇÒ ¶§
1. ¹Ý Á¤µµÀÇ ¹°ÀÌ Â÷ÀÖ´Â ³ÐÀÌ
2. Àüü ³ÐÀÌ
 
ÀÌ µÑ Áß ¾î´À°É·Î °è»êÇØ¾ß µÇ´Â °ÍÀΰ¡¿ä?
 
TypingÇϱ⿣ ³Ê¹« º¹ÀâÇÏ¿© Á¦°¡ °è»êÇÑ °úÁ¤À» ½ºÄµÇÑ µÚ ÆÄÀÏ·Î ¿Ã·È½À´Ï´Ù.
150%·Î È®´ëÇؼ­ º¸½Ã¸é µÇ°Ú½À´Ï´Ù. °¨»çÇÕ´Ï´Ù...

¹é±Ý¾óÀ½ music3106   13-02-18 11:48
À¯µ¿ ºÎºÐÀÇ ´Ü¸éÀûÀ¸·Î ¾Ë°í ÀÖ½À´Ï´Ù. ¹°ÀÌ È帣´Â ºÎºÐÀÇ ¸éÀûÀ¸·Î °è»êÇØ¾ß ÇÏ´Ï 1¹øÀÌ ¸Â°Ú³×¿ä
½ºÅ×Æijë Stefano   13-02-21 17:31
(1) ¸Â½À´Ï´Ù.  ±×¸®°í 4¹è¸¦ ÇÏ´Â ÀÌÀ¯´Â ´Ü¸éÀÌ ¿øÀÇ °æ¿ì¿¡¼­ ºñ·ÔµÈ °ÍÀÔ´Ï´Ù.

p=¿øÀÇ µÑ·¹= ¥ð*d
a=¿øÀÇ ´Ü¸éÀû =¥ð*d^2/4

a/p = d/4 --->  d = 4* (a/d) = 4*(µµ°ü ´Ü¸éÀû/È帣´Â µµ°üÀÇ º®µÑ·¹) 

(2) ¹ÝÂë Â÷ÀÖ´Â °üÀÇ »ó´çÁ÷°æÀº ÁÖ·Î Åä¸ñ°øÇп¡¼­ ´Ù·ç°í Àִµ¥ °ø±â¿Í Á¢ÇѸéÀº È帧ÀúÇ×ÀÌ °ÅÀÇ ¾ø´Ù°í º¸±â ¶§¹®¿¡ Á¥¾î È帣´Â ±æÀÌ (wetted perimeter)´Â ¿·¸é°ú ¹Ù´Ú¸éÀÇ ±æÀ̸¸ °í·ÁÇÏ¸é µË´Ï´Ù.
dpffkqlwpf dpffkqlwpf   13-02-23 16:52
ÀÌÁ¦¾ß °³³äÀÌ ÀÌÇØ됬½À´Ï´Ù. '¹é±Ý¾óÀ½'´Ô, '½ºÅ×Æijë'´Ô. ´äº¯ °¨»çÇÕ´Ï´Ù.
   

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