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  ±Û¾´ÀÌ : ÇÁ¸®Æú   °íÀ¯ID : tlemfoql     ³¯Â¥ : 14-09-30 20:36     Á¶È¸ : 3976    
À̽ÄÀº ¹«¾ùÀ» ±¸Çϴ½ÄÀΰ¡¿ä... ÀúÁß¿¡ 2gcjºÎºÐÀÌ ¹«¾ùÀ»¶æÇϴ°ÇÁö ¸ð¸£°Ú½À´Ï´Ù ¤Ð

½ºÅ×Æijë Stefano   14-10-01 18:42
»óÅ¿¡¼­ b »óÅ·Πº¯È­ÇÏ´Â °úÁ¤¿¡¼­ ´ÜÀ§Áú·®´ç ¿­¿¡³ÊÁö¿Í ¿îµ¿¿¡³ÊÁö Áõ°¡·®À» ³ªÅ¸³»´Â ¼ö½ÄÀÔ´Ï´Ù.
¶Ç 1/2ÀÇ Àǹ̴ 1/2 m v^2¿¡ ÇØ´çÇÏ´Â ¿îµ¿¿¡³ÊÁö¸¦ ³ªÅ¸³¾¶§ÀÇ °è¼ö(1/2)¸¦ ÀǹÌÇÏ°í,
gc´Â  (kg-mass)*m/s^2 ´ÜÀ§ÀÇ ÈûÀÇ ¿¡³ÊÁö ´ÜÀ§¸¦ kgf´ÜÀ§·Î ȯ»êÇϱâ À§ÇÑ ´ÜÀ§È¯»ê°è¼öÀÌ°í
J´Â kgf-m (=J = N-m)´ÜÀ§ÀÇ ¿¡³ÊÁö´ÜÀ§¸¦ cal´ÜÀ§·Î ȯ»êÇϱâ À§ÇÑ È¯»ê°è¼öÀÔ´Ï´Ù.

gc = 9.8 (kgm/kgf)*m/s^2 = 9.8N/kgf, 
J = (1/4.184) N-m/cal =0.238 kN-m/kcal =0.238 kJ/kcal

¼ö½ÄÀÌ ³ªÅ¸³ª ÀÖ´Â ¹®ÇåÀÇ ¼³¸íÀ» ÀÚ¼¼È÷ Àоµµ·Ï Çϼ¼¿ä.
   

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