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  n2 ¼Ó¿¡ Æ÷ÇԵǾî ÀÖ´Â h2 mol% °è»ê½Ä
  ±Û¾´ÀÌ : ÀÌÇϴôԠ  °íÀ¯ID : cjcafe     ³¯Â¥ : 23-06-14 16:10     Á¶È¸ : 1721    
N2 °¡ 4000kg/hr µé¾î °¡°í ÀÖ°í H2 °¡ 37kg/hr µé¾î °¡°í ÀÖ´Â °æ¿ì
H2 ·®ÀÌ ¸î mol% ÀÎÁö ¾Ë·Á°í Çϴµ¥ ±¸ÇÏ´Â °è»ê½ÄÀ» ¾Ë¼ö ÀÖÀ»±î¿ä?
¿ª¼øÀ¸·Î À§¿Í °°Àº Á¶°Ç¿¡¼­ N2°¡ 4500kg/hr µé¾î °¡°í ÀÖÀ»¶§ H2¸¦ ³Ö¾ú´Âµ¥ ºÐ¼®°á°ú
H2°¡ 5.20mol%°¡ ³ª¿Ô´Ù¸é H2´Â ¸î kg/hr µé¾î°£°ÍÀÎÁö ¾Ë°í ½Í½À´Ï´Ù.
´äº¯¿¡ °¨»çµå¸²´Ï´Ù.

Stefano    23-06-14 21:58
ù¹®Á¦´Â System ³»¿¡ À¯ÀԵǴ ¹°Áú³»¿¡ µé¾îÀÖ´Â °¢ ¼ººÐÀÇ ¸ô¼ö(¸ôÀ¯·®)·ÎºÎÅÍ Àüü ¸ô¼ö(¸ôÀ¯·®)¸¦ ±¸ÇÑ ´ÙÀ½  °¢ ¼ººÐÀÇ ¸ôºñ·ÎºÎÅÍ ¸ô%³óµµ¸¦ ±¸ÇÏ¸é µË´Ï´Ù.  µÎ¹ø° ¹®Á¦´Â º¹ÀâÇѵí Çصµ 1)¼ö¼Ò ¸ô³óµµ(X2, x2)·ÎºÎÅÍ Áú¼Ò ¸ô³óµµ(X1, x1)¸¦ ¾Ë¼ö ÀÖ°í 2) Áú¼Ò¸ôÀ¯·®(n1)À¸·ÎºÎÅÍ  Àüü±âü ¸ôÀ¯·®(nt)À» ¾Ë¾Æ³½ ´ÙÀ½ 3) ¿©±â¿¡ ¼ö¼Ò¸ôºñ(x2)¸¦ °öÇÏ¸é  ¼ö¼ÒÀÇ ¸ôÀ¯·®(n2)À» ¾Ë ¼ö Àִµ¥ 4) ÀÌ °ª¿¡ ¼ö¼ÒºÐÀÚ·®(M2)À» °öÇÏ¸é ¼ö¼ÒÁú·®À¯·®(m2)ÀÌ °è»êµÇÁö¿ä.   

ni= mi/Mi = i ¼ººÐÀÇ ¸ôÀ¯·®  ....(1) [kg-mole/h],  Mi=i ¼ººÐ ºÐÀÚ·®[kg/kg-mole],  mi = i¼ººÐ Áú·®À¯·®[kg/h]

n1+ n2 + ..... =  nt ..............(2)  ni = i¼ººÐ ¸ôÀ¯·®[kg-mole_i Component/h],  nt=Àüü ¸ôÀ¯·®[kg-mole_Total/h]

n1/nt = x1,  n2/nt=x2, .........(3)  xi = i ¼ººÐ ¸ôºÐÀ² [mole/mole];  (Âü°í: x1 + x2 + ..= ¥Òxi= 1 ..(4) )

100%*(xi) = Xi %  ....(5)  Xi= i ¼ººÐ mol%³óµµ; mole ºÐÀ²À» mole %·Î ȯ»êÇÏ·Á¸é 100%¸¦ °öÇÔ.(Âü°í: ¥ÒXi=100%...(6)) 

À§ÀÇ 1~5½Ä¿¡  1= N2,  2=H2 ¸¦ Àû¿ëÇÏ¿©  ù¹ø¹®Á¦(m1=4000 kg_N2/h)¿Í µÎ¹ø° ¹®Á¦(m1=4500 kg_N2/h)¿¡ ´ëÇÏ¿©  ni, xi, Xi, mi ¸¦ Á÷Á¢ °è»êÇØ º¸¼¼¿ä  (M1=28.013 ,  M2=2.016 Àû¿ë)
     
ÀÌÇϴôԠcjcafe   23-06-17 18:43
´äº¯°¨»çÇÕ´Ï´Ù. Á¤´äÀÌ ¸Â´ÂÁö ºÁÁֽðھî¿ä?
ù¹ø°´Â N2¿Í H2 Àüü¸ô¼ö°¡ 160.55 ³ª¿Ô°í Æò±ÕºÐÀÚ·®Àº 0.03977 ·Î °è»êÀÌ µÇ¾ú½À´Ï´Ù.
±×·¡¼­ 0.3977 x 37 x 2.016 = 2.966 mol% °¡ ³ª¿Ô´Âµ¥ ¸Â´ÂÁö¿ä?

µÎ¹ø° ¹®Á¦´Â H2 °¡ 17.62 kh/hr ·Î °è»êÀÌ µÇ´Âµ¥ ¸Â´Â ´äÀΰ¡¿ä?
À§¿¡ ½ÄÀº ÀúÇѵ¥ ¾î·Á¿î°Å °°½À´Ï´Ù. Á»´õ ½±°Ô ¼ö½ÄÀ̳ª ¼ýÀÚµîÀ¸·Î ¾Ë·ÁÁÖ½Ã¸é °¨»çÇÏ°Ú½À´Ï´Ù.
½ºÅ×Æijë Stefano   23-06-17 21:50
(1)
n1 = 4,000/28.013 = 142.791 kg-mole-N2/h  n2 =37/2.016 =18.335 kg-mole-H2/h  nt=164.126 kg-mole/h   
x2= n2/nt = 0.1117 mole_H2/mole Total, 

¡Å  X2=11.17m% of Hydrogen

(2)
n1= 4,500/28.013 = 160.640 kg-mole-N2/h  X2 = 5.20 m%_H2,  x2=0.0520 mole_H2/mole Total
x1=1-0.052 = 0.9480  mole N2/mole Total   
x1 = n1/nt ==>  nt = n1/x1 = 160.640 kg-mole_N2/h/0.948 kg-mole_N2/kg-mole Total = 169.45 kg-mole Total/h 

n2 = x2*nt  ==>  n2= 0.0520*169.45 kgmole_H2/h =8.811kg_mole_H2/h; 
n2 =m2/M2 ==>  ¡Å m2=n2*M2 = 8.811 kg-mole_H2/h * (2.016 kg_H2/kg-mole_H2) = 17.764 kg_H2/h
     
ÀÌÇϴôԠcjcafe   23-06-18 13:23
´äº¯ °¨»çµå¸²´Ï´Ù. ÀÌÁ¦ ÀÌÇØ°¡ Á¶±Ý °¡³×¿ä. ¸¹Àº µµ¿òÀÌ µÇ¿òÀÌ µÇ¾ú½À´Ï´Ù. ^^
½ºÅ×Æijë Stefano   23-06-18 15:14
Æò±Õ ºÐÀÚ·® 0.03977ÀÌ ¿Ö °Å·ÐµÇ¾ú°í ¶Ç, ±×°ªÀÌ ¾î¶»°Ô ³ª¿Ô´ÂÁö ±Ã±ÝÇѵ¥... ¾î´À ¹°ÁúÀ̵çÁö Æò±ÕºÐÀÚ·®Àº ¼ö¼ÒÀÇ ºÐÀÚ·® 2.016º¸´Ù ÀÛ¾ÆÁú ¼ö ¾ø½À´Ï´Ù.  °¡Àå ºÐÀÚ·®ÀÌ ÀÛÀº ¹°ÁúÀÌ ¼ö¼ÒÀ̱⠶§¹®ÀÔ´Ï´Ù.  Æò±Õ ºÐÀÚ·®Àº ´ÙÀ½°ú °°ÀÌ °è»êÇÒ ¼ö ÀÖ½À´Ï´Ù. 

Æò±ÕºÐÀÚ·® = mt/nt = (n1*M1+n2*M2+...)/nt = x1*M1+x2*M2+ ..  = 0.8883*28.013 + 0.1117*2.016 = 25.109
   

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